((4(x+3))/5)-1=7

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Solution for ((4(x+3))/5)-1=7 equation: 



((4(x+3))/5)-1=7

We move all terms to the left:

((4(x+3))/5)-1-(7)=0

We add all the numbers together, and all the variables

((4(x+3))/5)-8=0

We multiply all the terms by the denominator


((4(x+3))-8*5)=0



We calculate terms in parentheses: +((4(x+3))-8*5), so:

(4(x+3))-8*5

We add all the numbers together, and all the variables

(4(x+3))-40



We calculate terms in parentheses: +(4(x+3)), so:

4(x+3)

We multiply parentheses

4x+12

Back to the equation:

+(4x+12)



We get rid of parentheses

4x+12-40

We add all the numbers together, and all the variables

4x-28

Back to the equation:

+(4x-28)



We get rid of parentheses

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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