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((4)/(3))*y=16
We move all terms to the left:
((4)/(3))*y-(16)=0
Domain of the equation: 3)*y!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
(+4/3)*y-16=0
We multiply parentheses
4y^2-16=0
a = 4; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·4·(-16)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16}{2*4}=\frac{-16}{8} =-2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16}{2*4}=\frac{16}{8} =2 $
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