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((4)/(7))(x-3)=((5)/(3))
We move all terms to the left:
((4)/(7))(x-3)-(((5)/(3)))=0
Domain of the equation: 7)(x-3)!=0We add all the numbers together, and all the variables
x∈R
(+4/7)(x-3)-((+5/3))=0
We multiply parentheses ..
(+4x^2+4/7*-3)-((+5/3))=0
We calculate fractions
4x^2/()+()/()=0
We add all the numbers together, and all the variables
4x^2/()+1=0
We multiply all the terms by the denominator
4x^2+1*()=0
We add all the numbers together, and all the variables
4x^2=0
a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{8}=0$
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