((4)/(x+2))+((3)/(x-5))=((7)/(x+4))

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Solution for ((4)/(x+2))+((3)/(x-5))=((7)/(x+4)) equation: 


D( x )

x-5 = 0

x+4 = 0

x+2 = 0

x-5 = 0

x-5 = 0

x-5 = 0 // + 5

x = 5

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x in (-oo:-4) U (-4:-2) U (-2:5) U (5:+oo)

4/(x+2)+3/(x-5) = 7/(x+4) // - 7/(x+4)

4/(x+2)+3/(x-5)-(7/(x+4)) = 0

4/(x+2)+3/(x-5)-7*(x+4)^-1 = 0

4/(x+2)+3/(x-5)-7/(x+4) = 0

(4*(x-5)*(x+4))/((x+2)*(x-5)*(x+4))+(3*(x+2)*(x+4))/((x+2)*(x-5)*(x+4))+(-7*(x+2)*(x-5))/((x+2)*(x-5)*(x+4)) = 0

4*(x-5)*(x+4)+3*(x+2)*(x+4)-7*(x+2)*(x-5) = 0

7*x^2-7*x^2+14*x+21*x-56+70 = 0

35*x+14 = 0

(35*x+14)/((x+2)*(x-5)*(x+4)) = 0

(35*x+14)/((x+2)*(x-5)*(x+4)) = 0 // * (x+2)*(x-5)*(x+4)

35*x+14 = 0

35*x+14 = 0 // - 14

35*x = -14 // : 35

x = -14/35

x = -2/5

x = -2/5

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