((4/5)x)+92=x

Solution for ((4/5)x)+92=x equation:

((4/5)x)+92=x

We move all terms to the left:

((4/5)x)+92-(x)=0


Domain of the equation: 5)x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

((+4/5)x)-x+92=0

We add all the numbers together, and all the variables

-1x+((+4/5)x)+92=0

We multiply all the terms by the denominator


-1x*5)x)+((+92*5)x)+4=0

We add all the numbers together, and all the variables

-1x*5)x)+(460x)+4=0

We add all the numbers together, and all the variables

-1x*5)x)+460x+4=0

Wy multiply elements

-5x^2=0

a = -5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-5)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-10}=0$