((4C-8)/60)/((2-C)/3)

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Solution for ((4C-8)/60)/((2-C)/3) equation: 


D( C )

(2-C)/3 = 0

(2-C)/3 = 0

(2-C)/3 = 0

2-C = 0 // - 2

-C = -2 // * -1

C = 2

C in (-oo:2) U (2:+oo)

((4*C-8)/60)/((2-C)/3) = 0

(3*(4*C-8))/(60*(2-C)) = 0

( 3 )

3 = 0

C belongs to the empty set

( 4*C-8 )

4*C-8 = 0 // + 8

4*C = 8 // : 4

C = 8/4

C = 2

C in { 2} 

C belongs to the empty set

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