((4b+5)/7)-((2b-4)/5)=1

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Solution for ((4b+5)/7)-((2b-4)/5)=1 equation: 


b in (-oo:+oo)

(4*b+5)/7-((2*b-4)/5) = 1 // - 1

(4*b+5)/7-((2*b-4)/5)-1 = 0

(4*b+5)/7+(-1*(2*b-4))/5-1 = 0

(5*(4*b+5))/(5*7)+(-1*7*(2*b-4))/(5*7)+(-1*5*7)/(5*7) = 0

5*(4*b+5)-1*7*(2*b-4)-1*5*7 = 0

6*b-35+53 = 0

6*b+18 = 0

(6*b+18)/(5*7) = 0

(6*b+18)/(5*7) = 0 // * 5*7

6*b+18 = 0

6*b+18 = 0 // - 18

6*b = -18 // : 6

b = -18/6

b = -3

b = -3

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