((4n-28)/3)=2n

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Solution for ((4n-28)/3)=2n equation: 



((4n-28)/3)=2n

We move all terms to the left:

((4n-28)/3)-(2n)=0

We add all the numbers together, and all the variables

-2n+((4n-28)/3)=0

We multiply all the terms by the denominator


-2n*3)+((4n-28)=0

Wy multiply elements

-6n^2=0

a = -6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-6)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{-12}=0$

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