((4x)/(x+1))=((4x-3)/(x-2))

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Solution for ((4x)/(x+1))=((4x-3)/(x-2)) equation: 


D( x )

x-2 = 0

x+1 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:2) U (2:+oo)

(4*x)/(x+1) = (4*x-3)/(x-2) // - (4*x-3)/(x-2)

(4*x)/(x+1)-((4*x-3)/(x-2)) = 0

(4*x)/(x+1)+(-1*(4*x-3))/(x-2) = 0

(4*x*(x-2))/((x+1)*(x-2))+(-1*(4*x-3)*(x+1))/((x+1)*(x-2)) = 0

4*x*(x-2)-1*(4*x-3)*(x+1) = 0

3-9*x = 0

(3-9*x)/((x+1)*(x-2)) = 0

(3-9*x)/((x+1)*(x-2)) = 0 // * (x+1)*(x-2)

3-9*x = 0

3-9*x = 0 // - 3

-9*x = -3 // : -9

x = -3/(-9)

x = 1/3

x = 1/3

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