((4x)/8)=(9/4)

Solution for ((4x)/8)=(9/4) equation:

((4x)/8)=(9/4)

We move all terms to the left:

((4x)/8)-((9/4))=0

We add all the numbers together, and all the variables

(+4x/8)-((+9/4))=0

We get rid of parentheses

4x/8-((+9/4))=0

We calculate fractions


16x^2/()+()/()=0

We add all the numbers together, and all the variables

16x^2/()+1=0

We multiply all the terms by the denominator


16x^2+1*()=0

We add all the numbers together, and all the variables

16x^2=0

a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{32}=0$