((4x+1)/4)-((2x+3)/3)=7/12

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Solution for ((4x+1)/4)-((2x+3)/3)=7/12 equation: 



((4x+1)/4)-((2x+3)/3)=7/12

We move all terms to the left:

((4x+1)/4)-((2x+3)/3)-(7/12)=0

We add all the numbers together, and all the variables

((4x+1)/4)-((2x+3)/3)-(+7/12)=0

We get rid of parentheses

((4x+1)/4)-((2x+3)/3)-7/12=0

We calculate fractions


(((4x+1)*3)*12)/()+(-((2x+3)*4)*12)/()+()/()=0



We calculate terms in parentheses: +(((4x+1)*3)*12)/(), so:

((4x+1)*3)*12)/(

We multiply all the terms by the denominator


((4x+1)*3)*12)



We calculate terms in parentheses: +((4x+1)*3)*12), so:

(4x+1)*3)*12

We multiply parentheses

48x+

We add all the numbers together, and all the variables

48x

Back to the equation:

+(48x)



Back to the equation:

+(48x)





We calculate terms in parentheses: +(-((2x+3)*4)*12)/(), so:

-((2x+3)*4)*12)/(

We multiply all the terms by the denominator


-((2x+3)*4)*12)



We calculate terms in parentheses: -((2x+3)*4)*12), so:

(2x+3)*4)*12

We multiply parentheses

24x+

We add all the numbers together, and all the variables

24x

Back to the equation:

-(24x)



Back to the equation:

+(-24x)



We add all the numbers together, and all the variables

48x+(-24x)+1=0

We get rid of parentheses

48x-24x+1=0

We add all the numbers together, and all the variables

24x+1=0

We move all terms containing x to the left, all other terms to the right

24x=-1

x=-1/24

x=-1/24

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