((4x+12)/3)-8=9x

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Solution for ((4x+12)/3)-8=9x equation: 



((4x+12)/3)-8=9x

We move all terms to the left:

((4x+12)/3)-8-(9x)=0

We add all the numbers together, and all the variables

-9x+((4x+12)/3)-8=0

We multiply all the terms by the denominator


-9x*3)+((4x+12)-8*3)=0

We add all the numbers together, and all the variables

-9x*3)+((4x+12)=0

Wy multiply elements

-27x^2=0

a = -27; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-27)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-54}=0$

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