((4x-8)/6)-8=4/5x-4x-12

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Solution for ((4x-8)/6)-8=4/5x-4x-12 equation: 



((4x-8)/6)-8=4/5x-4x-12

We move all terms to the left:

((4x-8)/6)-8-(4/5x-4x-12)=0



Domain of the equation: 5x-4x-12)!=0

x∈R



We add all the numbers together, and all the variables

((4x-8)/6)-(-4x+4/5x-12)-8=0

We get rid of parentheses

((4x-8)/6)+4x-4/5x+12-8=0

We calculate fractions


4x+(((4x-8)*5x)/6*5x)+()/6*5x)+12-8=0



We calculate terms in parentheses: +(((4x-8)*5x)/6*5x), so:

((4x-8)*5x)/6*5x

We multiply all the terms by the denominator


((4x-8)*5x)



We calculate terms in parentheses: +((4x-8)*5x), so:

(4x-8)*5x

We multiply parentheses

20x^2-40x

Back to the equation:

+(20x^2-40x)



We get rid of parentheses

20x^2-40x

Back to the equation:

+(20x^2-40x)



We get rid of parentheses

20x^2+4x-40x+()/6*5x)+12-8=0

We multiply all the terms by the denominator


20x^2*6*5x)+12-8+4x*6*5x)+12-8-40x*6*5x)+12-8+()=0

Wy multiply elements

540000x^5*5=0

We do not support expression: x^5

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