((4y+1)/3)-((2y+1)/5)=3/5

Solution for ((4y+1)/3)-((2y+1)/5)=3/5 equation:

((4y+1)/3)-((2y+1)/5)=3/5

We move all terms to the left:

((4y+1)/3)-((2y+1)/5)-(3/5)=0

We add all the numbers together, and all the variables

((4y+1)/3)-((2y+1)/5)-(+3/5)=0

We get rid of parentheses

((4y+1)/3)-((2y+1)/5)-3/5=0

We calculate fractions


(((4y+1)*5)*5)/()+(-6y-3)/()+()/()=0


We calculate terms in parentheses: +(((4y+1)*5)*5)/(), so:

((4y+1)*5)*5)/(

We multiply all the terms by the denominator


((4y+1)*5)*5)


We calculate terms in parentheses: +((4y+1)*5)*5), so:

(4y+1)*5)*5

We multiply parentheses

20y+

We add all the numbers together, and all the variables

20y

Back to the equation:

+(20y)


Back to the equation:

+(20y)


We add all the numbers together, and all the variables

20y+(-6y-3)/()+1=0

We multiply all the terms by the denominator


20y*()+(-6y-3)+1*()=0

We add all the numbers together, and all the variables

20y*()+(-6y-3)=0

We get rid of parentheses

20y*()-6y-3=0

We add all the numbers together, and all the variables

-6y+20y*()-3=0

We move all terms containing y to the left, all other terms to the right

-6y+20y*()=3