((5(x-3))/6)-x=1-(x/9)

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Solution for ((5(x-3))/6)-x=1-(x/9) equation: 



((5(x-3))/6)-x=1-(x/9)

We move all terms to the left:

((5(x-3))/6)-x-(1-(x/9))=0

We add all the numbers together, and all the variables

((5(x-3))/6)-x-(1-(+x/9))=0

We add all the numbers together, and all the variables

-1x+((5(x-3))/6)-(1-(+x/9))=0

We calculate fractions


-1x+45x/()+(-(-(x*6+1))/()=0



We calculate terms in parentheses: +(-(-(x*6+1))/(), so:

-(-(x*6+1))/(

We multiply all the terms by the denominator


-(-(x*6+1))



We calculate terms in parentheses: -(-(x*6+1)), so:

-(x*6+1)

We get rid of parentheses

-x*6-1

Wy multiply elements

-6x-1

Back to the equation:

-(-6x-1)



We get rid of parentheses

6x+1

Back to the equation:

+(6x+1)



We get rid of parentheses

-1x+45x/()+6x+1=0

We multiply all the terms by the denominator


-1x*()+45x+6x*()+1*()=0

We add all the numbers together, and all the variables

45x-1x*()+6x*()=0

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