((5/2y)+20)/(y-20)=3

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Solution for ((5/2y)+20)/(y-20)=3 equation: 


D( y )

y-20 = 0

y-20 = 0

y-20 = 0

y-20 = 0 // + 20

y = 20

y in (-oo:20) U (20:+oo)

((5/2)*y+20)/(y-20) = 3 // - 3

((5/2)*y+20)/(y-20)-3 = 0

(5/2*y+20)/(y-20)-3 = 0

(5/2*y+20)/(y-20)+(-3*(y-20))/(y-20) = 0

5/2*y-3*(y-20)+20 = 0

80-1/2*y = 0

(80-1/2*y)/(y-20) = 0

(80-1/2*y)/(y-20) = 0 // * y-20

80-1/2*y = 0

80-1/2*y = 0 // - 80

-1/2*y = -80 // : -1/2

y = -80/(-1/2)

y = 160

y = 160

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