((5/4x-(12x)+5x)(12-13x)+125)=(((48x-29)-(28x+2)-12x)-14x-12-13x)

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Solution for ((5/4x-(12x)+5x)(12-13x)+125)=(((48x-29)-(28x+2)-12x)-14x-12-13x) equation: 



((5/4x-(12x)+5x)(12-13x)+125)=(((48x-29)-(28x+2)-12x)-14x-12-13x)

We move all terms to the left:

((5/4x-(12x)+5x)(12-13x)+125)-((((48x-29)-(28x+2)-12x)-14x-12-13x))=0



Domain of the equation: 4x-12x+5x)(12-13x)+125)!=0

x∈R



We add all the numbers together, and all the variables

((-7x+5/4x)(-13x+12)+125)-((((48x-29)-(28x+2)-12x)-14x-12-13x))=0

We multiply parentheses ..

((+91x^2-84x-65x^2+60x)+125)-((((48x-29)-(28x+2)-12x)-14x-12-13x))=0



We calculate terms in parentheses: +((+91x^2-84x-65x^2+60x)+125), so:

(+91x^2-84x-65x^2+60x)+125

We get rid of parentheses

91x^2-65x^2-84x+60x+125

We add all the numbers together, and all the variables

26x^2-24x+125

Back to the equation:

+(26x^2-24x+125)





We calculate terms in parentheses: -((((48x-29)-(28x+2)-12x)-14x-12-13x)), so:

(((48x-29)-(28x+2)-12x)-14x-12-13x)



We calculate terms in parentheses: +(((48x-29)-(28x+2)-12x)-14x-12-13x), so:

((48x-29)-(28x+2)-12x)-14x-12-13x

determiningTheFunctionDomain
((48x-29)-(28x+2)-12x)-14x-13x-12

We add all the numbers together, and all the variables

-27x+((48x-29)-(28x+2)-12x)-12



We calculate terms in parentheses: +((48x-29)-(28x+2)-12x), so:

(48x-29)-(28x+2)-12x

We add all the numbers together, and all the variables

-12x+(48x-29)-(28x+2)

We get rid of parentheses

-12x+48x-28x-29-2

We add all the numbers together, and all the variables

8x-31

Back to the equation:

+(8x-31)



We get rid of parentheses

-27x+8x-31-12

We add all the numbers together, and all the variables

-19x-43

Back to the equation:

+(-19x-43)



We get rid of parentheses

-19x-43

Back to the equation:

-(-19x-43)



We get rid of parentheses

26x^2-24x+19x+125+43=0

We add all the numbers together, and all the variables

26x^2-5x+168=0

a = 26; b = -5; c = +168;
Δ = b2-4ac
Δ = -52-4·26·168
Δ = -17447
Delta is less than zero, so there is no solution for the equation

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