((5b-5)/5)-((b-2)/5)=1

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Solution for ((5b-5)/5)-((b-2)/5)=1 equation: 


b in (-oo:+oo)

(5*b-5)/5-((b-2)/5) = 1 // - 1

(5*b-5)/5-((b-2)/5)-1 = 0

(5*b-5)/5+(-1*(b-2))/5-1 = 0

(5*b-5)/5+(-1*(b-2))/5+(-1*5)/5 = 0

5*b-1*(b-2)-1*5-5 = 0

4*b-5-3 = 0

4*b-8 = 0

(4*b-8)/5 = 0

(4*b-8)/5 = 0 // * 5

4*b-8 = 0

4*b-8 = 0 // + 8

4*b = 8 // : 4

b = 8/4

b = 2

b = 2

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