((5u-5)/2)=((7u-6)/3)+1

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Solution for ((5u-5)/2)=((7u-6)/3)+1 equation: 


u in (-oo:+oo)

(5*u-5)/2 = (7*u-6)/3+1 // - (7*u-6)/3+1

(5*u-5)/2-((7*u-6)/3)-1 = 0

(5*u-5)/2+(-1*(7*u-6))/3-1 = 0

(3*(5*u-5))/(2*3)+(-1*2*(7*u-6))/(2*3)+(-1*2*3)/(2*3) = 0

3*(5*u-5)-1*2*(7*u-6)-1*2*3 = 0

u-6-3 = 0

u-9 = 0

(u-9)/(2*3) = 0

(u-9)/(2*3) = 0 // * 2*3

u-9 = 0

u-9 = 0 // + 9

u = 9

u = 9

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