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((5x+3)/2)-5=(5x-4)/4
We move all terms to the left:
((5x+3)/2)-5-((5x-4)/4)=0
We calculate fractions
(20x+12)/()+(-10x+8)/()-5=0
We multiply all the terms by the denominator
(20x+12)+(-10x+8)-5*()=0
We add all the numbers together, and all the variables
(20x+12)+(-10x+8)=0
We get rid of parentheses
20x-10x+12+8=0
We add all the numbers together, and all the variables
10x+20=0
We move all terms containing x to the left, all other terms to the right
10x=-20
x=-20/10
x=-2
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