((5x+5)/(3)/((6)/(40x+40)))

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Solution for ((5x+5)/(3)/((6)/(40x+40))) equation: 


D( x )

40*x+40 = 0

6/(40*x+40) = 0

40*x+40 = 0

40*x+40 = 0

40*x+40 = 0 // - 40

40*x = -40 // : 40

x = -40/40

x = -1

6/(40*x+40) = 0

6/(40*x+40) = 0

x in (-oo:-1) U (-1:+oo)

((5*x+5)/3)/(6/(40*x+40)) = 0

((5*x+5)*(40*x+40))/(3*6) = 0

( 40*x+40 )

40*x+40 = 0 // - 40

40*x = -40 // : 40

x = -40/40

x = -1

( 5*x+5 )

5*x+5 = 0 // - 5

5*x = -5 // : 5

x = -5/5

x = -1

x in { -1} 

x belongs to the empty set

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