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((5x-6)(5x-6))=x+8
We move all terms to the left:
((5x-6)(5x-6))-(x+8)=0
We get rid of parentheses
((5x-6)(5x-6))-x-8=0
We multiply parentheses ..
((+25x^2-30x-30x+36))-x-8=0
We calculate terms in parentheses: +((+25x^2-30x-30x+36)), so:We add all the numbers together, and all the variables
(+25x^2-30x-30x+36)
We get rid of parentheses
25x^2-30x-30x+36
We add all the numbers together, and all the variables
25x^2-60x+36
Back to the equation:
+(25x^2-60x+36)
-1x+(25x^2-60x+36)-8=0
We get rid of parentheses
25x^2-1x-60x+36-8=0
We add all the numbers together, and all the variables
25x^2-61x+28=0
a = 25; b = -61; c = +28;
Δ = b2-4ac
Δ = -612-4·25·28
Δ = 921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-61)-\sqrt{921}}{2*25}=\frac{61-\sqrt{921}}{50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-61)+\sqrt{921}}{2*25}=\frac{61+\sqrt{921}}{50} $
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