((5y)/(2y-1))-3=12/(2y-1)

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Solution for ((5y)/(2y-1))-3=12/(2y-1) equation: 


D( y )

2*y-1 = 0

2*y-1 = 0

2*y-1 = 0

2*y-1 = 0 // + 1

2*y = 1 // : 2

y = 1/2

y in (-oo:1/2) U (1/2:+oo)

(5*y)/(2*y-1)-3 = 12/(2*y-1) // - 12/(2*y-1)

(5*y)/(2*y-1)-(12/(2*y-1))-3 = 0

(5*y)/(2*y-1)-12*(2*y-1)^-1-3 = 0

(5*y)/(2*y-1)-12/(2*y-1)-3 = 0

(5*y)/(2*y-1)-12/(2*y-1)+(-3*(2*y-1))/(2*y-1) = 0

5*y-3*(2*y-1)-12 = 0

5*y-6*y-12+3 = 0

-y-9 = 0

(-y-9)/(2*y-1) = 0

(-y-9)/(2*y-1) = 0 // * 2*y-1

-y-9 = 0

-y-9 = 0 // + 9

-y = 9 // * -1

y = -9

y = -9

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