((6-2y)/5)+4y=-12

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Solution for ((6-2y)/5)+4y=-12 equation: 



((6-2y)/5)+4y=-12

We move all terms to the left:

((6-2y)/5)+4y-(-12)=0

We add all the numbers together, and all the variables

((-2y+6)/5)+4y-(-12)=0

We add all the numbers together, and all the variables

4y+((-2y+6)/5)+12=0

We multiply all the terms by the denominator


4y*5)+((-2y+6)+12*5)=0

We add all the numbers together, and all the variables

4y*5)+((-2y+6)=0

Wy multiply elements

20y^2=0

a = 20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·20·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{40}=0$

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