((6x+5)(4x+8))/2=A

Solution for ((6x+5)(4x+8))/2=A equation:

((6x+5)(4x+8))/2=

We move all terms to the left:

((6x+5)(4x+8))/2-()=0

We add all the numbers together, and all the variables

((6x+5)(4x+8))/2=0

We multiply parentheses ..

((+24x^2+48x+20x+40))/2=0

We multiply all the terms by the denominator


((+24x^2+48x+20x+40))=0


We calculate terms in parentheses: +((+24x^2+48x+20x+40)), so:

(+24x^2+48x+20x+40)

We get rid of parentheses

24x^2+48x+20x+40

We add all the numbers together, and all the variables

24x^2+68x+40

Back to the equation:

+(24x^2+68x+40)


We get rid of parentheses

24x^2+68x+40=0

a = 24; b = 68; c = +40;
Δ = b2-4ac
Δ = 682-4·24·40
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-28}{2*24}=\frac{-96}{48}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+28}{2*24}=\frac{-40}{48}
=-5/6
$