((6x+7)/7)-3=(5x-3)/8

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Solution for ((6x+7)/7)-3=(5x-3)/8 equation:



((6x+7)/7)-3=(5x-3)/8
We move all terms to the left:
((6x+7)/7)-3-((5x-3)/8)=0
We calculate fractions
(48x+56)/()+(-35x+21)/()-3=0
We multiply all the terms by the denominator
(48x+56)+(-35x+21)-3*()=0
We add all the numbers together, and all the variables
(48x+56)+(-35x+21)=0
We get rid of parentheses
48x-35x+56+21=0
We add all the numbers together, and all the variables
13x+77=0
We move all terms containing x to the left, all other terms to the right
13x=-77
x=-77/13
x=-5+12/13

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