((6x-12)/3)+4=18/x

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Solution for ((6x-12)/3)+4=18/x equation: 



((6x-12)/3)+4=18/x

We move all terms to the left:

((6x-12)/3)+4-(18/x)=0



Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

((6x-12)/3)-(+18/x)+4=0

We get rid of parentheses

((6x-12)/3)-18/x+4=0

We calculate fractions


(((6x-12)*x)/3*x)+()/3*x)+4=0



We calculate terms in parentheses: +(((6x-12)*x)/3*x), so:

((6x-12)*x)/3*x

We multiply all the terms by the denominator


((6x-12)*x)



We calculate terms in parentheses: +((6x-12)*x), so:

(6x-12)*x

We multiply parentheses

6x^2-12x

Back to the equation:

+(6x^2-12x)



We get rid of parentheses

6x^2-12x

Back to the equation:

+(6x^2-12x)



We get rid of parentheses

6x^2-12x+()/3*x)+4=0

We multiply all the terms by the denominator


6x^2*3*x)+4-12x*3*x)+4+()=0

Wy multiply elements

54x^4*x=0

We do not support expression: x^4

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