((7x)/5)-((3+2x)/2)=((x-10)/3)+2

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Solution for ((7x)/5)-((3+2x)/2)=((x-10)/3)+2 equation: 


x in (-oo:+oo)

(7*x)/5-((2*x+3)/2) = (x-10)/3+2 // - (x-10)/3+2

(7*x)/5-((2*x+3)/2)-((x-10)/3)-2 = 0

(-1*(2*x+3))/2+(-1*(x-10))/3+(7*x)/5-2 = 0

(-1*3*5*(2*x+3))/(2*3*5)+(-1*2*5*(x-10))/(2*3*5)+(2*3*7*x)/(2*3*5)+(-2*2*3*5)/(2*3*5) = 0

2*3*7*x-1*3*5*(2*x+3)-1*2*5*(x-10)-2*2*3*5 = 0

42*x-40*x-60+55 = 0

2*x-60+55 = 0

2*x-5 = 0

(2*x-5)/(2*3*5) = 0

(2*x-5)/(2*3*5) = 0 // * 2*3*5

2*x-5 = 0

2*x-5 = 0 // + 5

2*x = 5 // : 2

x = 5/2

x = 5/2

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