((7x+2)/5)+((x+3)/3)=-9

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Solution for ((7x+2)/5)+((x+3)/3)=-9 equation: 



((7x+2)/5)+((x+3)/3)=-9

We move all terms to the left:

((7x+2)/5)+((x+3)/3)-(-9)=0

We add all the numbers together, and all the variables

((7x+2)/5)+((x+3)/3)+9=0

We calculate fractions


(21x+6)/()+(5x+15)/()+9=0

We multiply all the terms by the denominator


(21x+6)+(5x+15)+9*()=0

We add all the numbers together, and all the variables

(21x+6)+(5x+15)=0

We get rid of parentheses

21x+5x+6+15=0

We add all the numbers together, and all the variables

26x+21=0

We move all terms containing x to the left, all other terms to the right

26x=-21

x=-21/26

x=-21/26

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