((7x+6)/5)+((2x-4)/7)=4

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Solution for ((7x+6)/5)+((2x-4)/7)=4 equation:



((7x+6)/5)+((2x-4)/7)=4
We move all terms to the left:
((7x+6)/5)+((2x-4)/7)-(4)=0
We calculate fractions
(49x+42)/()+(10x-20)/()-4=0
We multiply all the terms by the denominator
(49x+42)+(10x-20)-4*()=0
We add all the numbers together, and all the variables
(49x+42)+(10x-20)=0
We get rid of parentheses
49x+10x+42-20=0
We add all the numbers together, and all the variables
59x+22=0
We move all terms containing x to the left, all other terms to the right
59x=-22
x=-22/59
x=-22/59

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