((8x+11)+(9x-7))/2=8x+6

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Solution for ((8x+11)+(9x-7))/2=8x+6 equation: 



((8x+11)+(9x-7))/2=8x+6

We move all terms to the left:

((8x+11)+(9x-7))/2-(8x+6)=0

We get rid of parentheses

((8x+11)+(9x-7))/2-8x-6=0

We multiply all the terms by the denominator


((8x+11)+(9x-7))-8x*2-6*2=0



We calculate terms in parentheses: +((8x+11)+(9x-7)), so:

(8x+11)+(9x-7)

We get rid of parentheses

8x+9x+11-7

We add all the numbers together, and all the variables

17x+4

Back to the equation:

+(17x+4)



We add all the numbers together, and all the variables

(17x+4)-8x*2-12=0

Wy multiply elements

(17x+4)-16x-12=0

We get rid of parentheses

17x-16x+4-12=0

We add all the numbers together, and all the variables

x-8=0

We move all terms containing x to the left, all other terms to the right

x=8

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