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D( x )
2*x-3 = 0
2*x-3 = 0
2*x-3 = 0
2*x-3 = 0 // + 3
2*x = 3 // : 2
x = 3/2
x in (-oo:3/2) U (3/2:+oo)
((8*x-12)/5)*(10/(2*x-3)) = 0
(10*(8*x-12))/(5*(2*x-3)) = 0
8*x-12 = 0 // + 12
8*x = 12 // : 8
x = 12/8
x = 3/2
x in { 3/2}
x belongs to the empty set
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