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((9x-2)/2)+3=5x
We move all terms to the left:
((9x-2)/2)+3-(5x)=0
We add all the numbers together, and all the variables
-5x+((9x-2)/2)+3=0
We multiply all the terms by the denominator
-5x*2)+((9x-2)+3*2)=0
We add all the numbers together, and all the variables
-5x*2)+((9x-2)=0
Wy multiply elements
-10x^2=0
a = -10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-10)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-20}=0$
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