((9x-2)/2)+3=5x

Solution for ((9x-2)/2)+3=5x equation:

((9x-2)/2)+3=5x

We move all terms to the left:

((9x-2)/2)+3-(5x)=0

We add all the numbers together, and all the variables

-5x+((9x-2)/2)+3=0

We multiply all the terms by the denominator


-5x*2)+((9x-2)+3*2)=0

We add all the numbers together, and all the variables

-5x*2)+((9x-2)=0

Wy multiply elements

-10x^2=0

a = -10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-10)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-20}=0$