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((9x-81)-(2x-16))/(9x-54)=0
Domain of the equation: (9x-54)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
9x!=54
x!=54/9
x!=6
x∈R
((9x-81)-(2x-16))=0
We calculate terms in parentheses: +((9x-81)-(2x-16)), so:We get rid of parentheses
(9x-81)-(2x-16)
We get rid of parentheses
9x-2x-81+16
We add all the numbers together, and all the variables
7x-65
Back to the equation:
+(7x-65)
7x-65=0
We move all terms containing x to the left, all other terms to the right
7x=65
x=65/7
x=9+2/7
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