((X+1)/7)+((x+3)/3)=1

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Solution for ((X+1)/7)+((x+3)/3)=1 equation: 



((X+1)/7)+((X+3)/3)=1

We move all terms to the left:

((X+1)/7)+((X+3)/3)-(1)=0

We calculate fractions


(3X+3)/()+(7X+21)/()-1=0

We multiply all the terms by the denominator


(3X+3)+(7X+21)-1*()=0

We add all the numbers together, and all the variables

(3X+3)+(7X+21)=0

We get rid of parentheses

3X+7X+3+21=0

We add all the numbers together, and all the variables

10X+24=0

We move all terms containing X to the left, all other terms to the right

10X=-24

X=-24/10

X=-2+2/5

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