((X+2)/7)+((x+1)/3)=2

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Solution for ((X+2)/7)+((x+1)/3)=2 equation: 


x in (-oo:+oo)

(X+2)/7+(x+1)/3 = 2 // - 2

(X+2)/7+(x+1)/3-2 = 0

(3*(X+2))/(3*7)+(7*(x+1))/(3*7)+(-2*3*7)/(3*7) = 0

3*(X+2)+7*(x+1)-2*3*7 = 0

3*X+7*x-42+13 = 0

3*X+7*x-29 = 0

(3*X+7*x-29)/(3*7) = 0

(3*X+7*x-29)/(3*7) = 0 // * 3*7

3*X+7*x-29 = 0

3*X+7*x-29 = 0 // - 3*X-29

7*x = -(3*X-29) // : 7

x = (-(3*X-29))/7

x = (29-(3*X))/7

x = (29-(3*X))/7

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