((X+5)/4)+((x+3)/7)=2

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Solution for ((X+5)/4)+((x+3)/7)=2 equation: 



((X+5)/4)+((X+3)/7)=2

We move all terms to the left:

((X+5)/4)+((X+3)/7)-(2)=0

We calculate fractions


(7X+35)/()+(4X+12)/()-2=0

We multiply all the terms by the denominator


(7X+35)+(4X+12)-2*()=0

We add all the numbers together, and all the variables

(7X+35)+(4X+12)=0

We get rid of parentheses

7X+4X+35+12=0

We add all the numbers together, and all the variables

11X+47=0

We move all terms containing X to the left, all other terms to the right

11X=-47

X=-47/11

X=-4+3/11

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