((a+2)/3a)+((b-5)/5b)

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Solution for ((a+2)/3a)+((b-5)/5b) equation:


x in (-oo:+oo)

a*((a+2)/3)+b*((b-5)/5) = 0

(a*(a+2))/3+(b*(b-5))/5 = 0

(5*a*(a+2))/(3*5)+(3*b*(b-5))/(3*5) = 0

5*a*(a+2)+3*b*(b-5) = 0

5*a^2+10*a+3*b^2-15*b = 0

(5*a^2+10*a+3*b^2-15*b)/(3*5) = 0

(5*a^2+10*a+3*b^2-15*b)/(3*5) = 0 // * 3*5

5*a^2+10*a+3*b^2-15*b = 0

x belongs to the empty set

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