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((a+3)*a)=17.5
We move all terms to the left:
((a+3)*a)-(17.5)=0
We add all the numbers together, and all the variables
((a+3)*a)-17.5=0
We calculate terms in parentheses: +((a+3)*a), so:We get rid of parentheses
(a+3)*a
We multiply parentheses
a^2+3a
Back to the equation:
+(a^2+3a)
a^2+3a-17.5=0
a = 1; b = 3; c = -17.5;
Δ = b2-4ac
Δ = 32-4·1·(-17.5)
Δ = 79
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{79}}{2*1}=\frac{-3-\sqrt{79}}{2} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{79}}{2*1}=\frac{-3+\sqrt{79}}{2} $
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