((b-1)/4)+((2b-3)/4)=b-(1/2)

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Solution for ((b-1)/4)+((2b-3)/4)=b-(1/2) equation: 



((b-1)/4)+((2b-3)/4)=b-(1/2)

We move all terms to the left:

((b-1)/4)+((2b-3)/4)-(b-(1/2))=0

We add all the numbers together, and all the variables

((b-1)/4)+((2b-3)/4)-(b-(+1/2))=0

We calculate fractions


(5b-7)/()+(-(b-4)/()=0



We calculate terms in parentheses: +(-(b-4)/(), so:

-(b-4)/(

We multiply all the terms by the denominator


-(b-4)

We get rid of parentheses

-b+4

We add all the numbers together, and all the variables

-1b+4

Back to the equation:

+(-1b+4)



We get rid of parentheses

(5b-7)/()-1b+4=0

We multiply all the terms by the denominator


(5b-7)-1b*()+4*()=0

We add all the numbers together, and all the variables

(5b-7)-1b*()=0

We get rid of parentheses

5b-1b*()-7=0

We move all terms containing b to the left, all other terms to the right

5b-1b*()=7

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