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((b-1)/4)+((2b-3)/4)=b-1/2
We move all terms to the left:
((b-1)/4)+((2b-3)/4)-(b-1/2)=0
We add all the numbers together, and all the variables
((b-1)/4)+((2b-3)/4)-(+b-1/2)=0
We get rid of parentheses
((b-1)/4)+((2b-3)/4)-b+1/2=0
We calculate fractions
-b+(((b-1)+((2b-3)*2)/()+()/()=0
We calculate terms in parentheses: +(((b-1)+((2b-3)*2)/()+()/(), so:
((b-1)+((2b-3)*2)/()+()/(
We can not solve this equation
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