((m+6)/2)-((2m-2)/3)=3

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Solution for ((m+6)/2)-((2m-2)/3)=3 equation: 



((m+6)/2)-((2m-2)/3)=3

We move all terms to the left:

((m+6)/2)-((2m-2)/3)-(3)=0

We calculate fractions


(3m+18)/()+(-4m+4)/()-3=0

We multiply all the terms by the denominator


(3m+18)+(-4m+4)-3*()=0

We add all the numbers together, and all the variables

(3m+18)+(-4m+4)=0

We get rid of parentheses

3m-4m+18+4=0

We add all the numbers together, and all the variables

-1m+22=0

We move all terms containing m to the left, all other terms to the right

-m=-22

m=-22/-1

m=+22

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