((n+1)(n+2)(2n+3))/6

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Solution for ((n+1)(n+2)(2n+3))/6 equation: 


n in (-oo:+oo)

((n+1)*(n+2)*(2*n+3))/6 = 0

( 2*n+3 )

2*n+3 = 0 // - 3

2*n = -3 // : 2

n = -3/2

( n+1 )

n+1 = 0 // - 1

n = -1

( n+2 )

n+2 = 0 // - 2

n = -2

n in { -3/2, -1, -2 }

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