((n+4)*5-(n+4))=33

Solution for ((n+4)*5-(n+4))=33 equation:

Simplifying
((n + 4) * 5 + -1(n + 4)) = 33

Reorder the terms:
((4 + n) * 5 + -1(n + 4)) = 33

Reorder the terms for easier multiplication:
(5(4 + n) + -1(n + 4)) = 33
((4 * 5 + n * 5) + -1(n + 4)) = 33
((20 + 5n) + -1(n + 4)) = 33

Reorder the terms:
(20 + 5n + -1(4 + n)) = 33
(20 + 5n + (4 * -1 + n * -1)) = 33
(20 + 5n + (-4 + -1n)) = 33

Reorder the terms:
(20 + -4 + 5n + -1n) = 33

Combine like terms: 20 + -4 = 16
(16 + 5n + -1n) = 33

Combine like terms: 5n + -1n = 4n
(16 + 4n) = 33

Remove parenthesis around (16 + 4n)
16 + 4n = 33

Solving
16 + 4n = 33

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + 4n = 33 + -16

Combine like terms: 16 + -16 = 0
0 + 4n = 33 + -16
4n = 33 + -16

Combine like terms: 33 + -16 = 17
4n = 17

Divide each side by '4'.
n = 4.25

Simplifying
n = 4.25