((t+2)/2)+2t=3

Solution for ((t+2)/2)+2t=3 equation:

((t+2)/2)+2t=3

We move all terms to the left:

((t+2)/2)+2t-(3)=0

We add all the numbers together, and all the variables

2t+((t+2)/2)-3=0

We multiply all the terms by the denominator


2t*2)+((t+2)-3*2)=0

We add all the numbers together, and all the variables

2t*2)+((t+2)=0

Wy multiply elements

4t^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{8}=0$