((t+2)/3)+((t+5)/4)=6

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Solution for ((t+2)/3)+((t+5)/4)=6 equation: 



((t+2)/3)+((t+5)/4)=6

We move all terms to the left:

((t+2)/3)+((t+5)/4)-(6)=0

We calculate fractions


(4t+8)/()+(3t+15)/()-6=0

We multiply all the terms by the denominator


(4t+8)+(3t+15)-6*()=0

We add all the numbers together, and all the variables

(4t+8)+(3t+15)=0

We get rid of parentheses

4t+3t+8+15=0

We add all the numbers together, and all the variables

7t+23=0

We move all terms containing t to the left, all other terms to the right

7t=-23

t=-23/7

t=-3+2/7

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