((v+1)/(v-3))=((v+7)/(v-5)+1)

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Solution for ((v+1)/(v-3))=((v+7)/(v-5)+1) equation: 


D( v )

v-3 = 0

v-5 = 0

v-3 = 0

v-3 = 0

v-3 = 0 // + 3

v = 3

v-5 = 0

v-5 = 0

v-5 = 0 // + 5

v = 5

v in (-oo:3) U (3:5) U (5:+oo)

(v+1)/(v-3) = (v+7)/(v-5)+1 // - (v+7)/(v-5)+1

(v+1)/(v-3)-((v+7)/(v-5))-1 = 0

(v+1)/(v-3)+(-1*(v+7))/(v-5)-1 = 0

((v+1)*(v-5))/((v-3)*(v-5))+(-1*(v+7)*(v-3))/((v-3)*(v-5))+(-1*(v-3)*(v-5))/((v-3)*(v-5)) = 0

(v+1)*(v-5)-1*(v+7)*(v-3)-1*(v-3)*(v-5) = 0

8*v-v^2-8*v-15+16 = 0

1-v^2 = 0

(1-v^2)/((v-3)*(v-5)) = 0

(1-v^2)/((v-3)*(v-5)) = 0 // * (v-3)*(v-5)

1-v^2 = 0

-1*v^2 = -1 // : -1

v^2 = 1

v^2 = 1 // ^ 1/2

abs(v) = 1

v = 1 or v = -1

v in { 1, -1 }

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