((v+4)/(v+3))+1=(v-7)/(v-1)

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Solution for ((v+4)/(v+3))+1=(v-7)/(v-1) equation: 


D( v )

v+3 = 0

v-1 = 0

v+3 = 0

v+3 = 0

v+3 = 0 // - 3

v = -3

v-1 = 0

v-1 = 0

v-1 = 0 // + 1

v = 1

v in (-oo:-3) U (-3:1) U (1:+oo)

(v+4)/(v+3)+1 = (v-7)/(v-1) // - (v-7)/(v-1)

(v+4)/(v+3)-((v-7)/(v-1))+1 = 0

(v+4)/(v+3)+(-1*(v-7))/(v-1)+1 = 0

((v+4)*(v-1))/((v+3)*(v-1))+(-1*(v-7)*(v+3))/((v+3)*(v-1))+(1*(v+3)*(v-1))/((v+3)*(v-1)) = 0

(v+4)*(v-1)-1*(v-7)*(v+3)+1*(v+3)*(v-1) = 0

v^2+7*v+2*v-3+17 = 0

v^2+9*v+14 = 0

v^2+9*v+14 = 0

v^2+9*v+14 = 0

DELTA = 9^2-(1*4*14)

DELTA = 25

DELTA > 0

v = (25^(1/2)-9)/(1*2) or v = (-25^(1/2)-9)/(1*2)

v = -2 or v = -7

(v+7)*(v+2) = 0

((v+7)*(v+2))/((v+3)*(v-1)) = 0

((v+7)*(v+2))/((v+3)*(v-1)) = 0 // * (v+3)*(v-1)

(v+7)*(v+2) = 0

( v+2 )

v+2 = 0 // - 2

v = -2

( v+7 )

v+7 = 0 // - 7

v = -7

v in { -2, -7 }

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