((v+4)/(v-5))+1=((v-3)/(v-1))

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Solution for ((v+4)/(v-5))+1=((v-3)/(v-1)) equation: 


D( v )

v-5 = 0

v-1 = 0

v-5 = 0

v-5 = 0

v-5 = 0 // + 5

v = 5

v-1 = 0

v-1 = 0

v-1 = 0 // + 1

v = 1

v in (-oo:1) U (1:5) U (5:+oo)

(v+4)/(v-5)+1 = (v-3)/(v-1) // - (v-3)/(v-1)

(v+4)/(v-5)-((v-3)/(v-1))+1 = 0

(v+4)/(v-5)+(-1*(v-3))/(v-1)+1 = 0

((v+4)*(v-1))/((v-5)*(v-1))+(-1*(v-3)*(v-5))/((v-5)*(v-1))+(1*(v-5)*(v-1))/((v-5)*(v-1)) = 0

(v+4)*(v-1)-1*(v-3)*(v-5)+1*(v-5)*(v-1) = 0

v^2+11*v-6*v-19+5 = 0

v^2+5*v-14 = 0

v^2+5*v-14 = 0

v^2+5*v-14 = 0

DELTA = 5^2-(-14*1*4)

DELTA = 81

DELTA > 0

v = (81^(1/2)-5)/(1*2) or v = (-81^(1/2)-5)/(1*2)

v = 2 or v = -7

(v+7)*(v-2) = 0

((v+7)*(v-2))/((v-5)*(v-1)) = 0

((v+7)*(v-2))/((v-5)*(v-1)) = 0 // * (v-5)*(v-1)

(v+7)*(v-2) = 0

( v+7 )

v+7 = 0 // - 7

v = -7

( v-2 )

v-2 = 0 // + 2

v = 2

v in { -7, 2 }

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