((v+5)/(v-3))=((v+7)/(v-5)+1)

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Solution for ((v+5)/(v-3))=((v+7)/(v-5)+1) equation: 


D( v )

v-3 = 0

v-5 = 0

v-3 = 0

v-3 = 0

v-3 = 0 // + 3

v = 3

v-5 = 0

v-5 = 0

v-5 = 0 // + 5

v = 5

v in (-oo:3) U (3:5) U (5:+oo)

(v+5)/(v-3) = (v+7)/(v-5)+1 // - (v+7)/(v-5)+1

(v+5)/(v-3)-((v+7)/(v-5))-1 = 0

(v+5)/(v-3)+(-1*(v+7))/(v-5)-1 = 0

((v+5)*(v-5))/((v-3)*(v-5))+(-1*(v+7)*(v-3))/((v-3)*(v-5))+(-1*(v-3)*(v-5))/((v-3)*(v-5)) = 0

(v+5)*(v-5)-1*(v+7)*(v-3)-1*(v-3)*(v-5) = 0

8*v-v^2-4*v-15-4 = 0

4*v-v^2-19 = 0

4*v-v^2-19 = 0

4*v-v^2-19 = 0

DELTA = 4^2-(-19*(-1)*4)

DELTA = -60

DELTA < 0

1 = 0

1/((v-3)*(v-5)) = 0

1/((v-3)*(v-5)) = 0 // * (v-3)*(v-5)

1 = 0

v belongs to the empty set

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